2x^2+8=8x+18

Solution for 2x^2+8=8x+18 equation:

2x^2+8=8x+18

We move all terms to the left:

2x^2+8-(8x+18)=0

We get rid of parentheses

2x^2-8x-18+8=0

We add all the numbers together, and all the variables

2x^2-8x-10=0

a = 2; b = -8; c = -10;
Δ = b2-4ac
Δ = -82-4·2·(-10)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-12}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+12}{2*2}=\frac{20}{4}
=5
$